Question

What amount of water contains the same number of hydrogen as contained by 68 gram of ammonia?​

Answer 1

amount of water = 108 g

mass of ammonia, (NH3) = 68gram

as we know molecular mass of ammonia = 17g/mol

so, no of moles of ammonia = 68g/17g/mol = 4 mol

in one molecule of ammonia contains three hydrogen atoms.

so, no of mole of hydrogen atoms = 3 × no of mole of ammonia

= 3 × 4 = 12 mol

now in case of water (H2O) two hydrogen atoms is present in one molecule of water.

so, 2 × no of mole of water = no of moles of hydrogen atoms in water

or, no of moles of water = 12/2 = 6 mol

molecular mass of water = 18g/mol

so, mass of water = 18 × 6 = 108g

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