Question

what amount of water is added in 40 ml of NaoH (0.1N) WHICH IS NEUTRALISE BY 50 ML OF HCL (0.2N)

Answer 1

no of equivalents of NaOH= no of euivalents of HCl

(40+x)0.1=50*0.2

100=40+x

x=60

therefore 60ml of water should be added