What are all abc identities
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(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
Answered by
0
(a+b+c)²=a²+b²+c²+2ab +2bc +2ca
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
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