Question

what are all the isomers of alcohols differencing only in the position of - oh with molecular formula C5H100​

Answer 1

Answer:

Explanation:

The IUPAC name of the compound having the molecular formula of C5H10O can be either cyclopentanol or pent-2-en-1-ol if we consider it to be an alcohol. (By the way numbers of isomers for aldehyde and ketone can be found out.).

There are no possible isomers for cyclopentanol, because -OH position will be equivalent at all the 5 carbons.

In case of Pent-2-en-1-ol, if you ask for isomers having -OH at different positions, then there will be no possible isomers either. This is because in this case, -OH group has higher priority over the double bond. So according to the nomenclature rules defined by IUPAC, we have to select the longest carbon chain containing the functional group. So wherever you place the -OH group, The carbon attached to it will always be counted as number one and thus there will be no difference in the placement of -OH group.

Answer 2

Explanation:

Pentenes. 1-Pentene (CAS 109-67-1) cis-2-Pentene (CAS 627-20-3) trans-2-pentene (CAS 646-04-8)

Butenes. 2-Methyl-1-butene (CAS 563-46-2) 3-Methyl-1-butene (CAS 563-45-1) 2-Methyl-2-butene (CAS 513-35-9)