Question

what are Karewa formation​

Answer 1

Answer:

We have p(x)=10x−4x

2

−3

∴p(0)=10(0)−4(0)

2

−3

∴p(0)=0−0−3=−3

p(1)=10(1)−4(1)

2

−3

∴p(1)=10−4−3=3

And,

p(−2)=10(−2)−4(−2)

2

−3

∴p(−2)=−20−4(4)−3=−20−16−3=−39

Answer 2

Answer:

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