Question

WHAT ARE THE COORDINATES OF THE POINT OF INTERSECTION OF THE GRAPH OF EQUATION 3x+4y= -6 with the y axis?
1) (-2/3,0)
2) (0,-2/3)
3) (-3/2,0)
4) (0,-3/2)

Answer 1

Answer:

(0,-3/2)

Step-by-step explanation:

we know the equation of y-axis :-

x=0

so when we put the value in the other equation

$3 \times 0 + 4y = - 6 \\ 4y = - 6 \\ y = \frac{ - 6}{4} = - \frac{3}{2}$

so (0, -3/2)

Answer 2

Answer:

PLEASE MARK IT AS BRILLIANT

Step-by-step explanation:

The coordinates of points of intersection of graph of equation 3x-4y=-63x−4y=−6 with y-axis is (0,\frac{3}{2})(0,23) .

Step-by-step explanation:

Given : Points of intersection of graph of equation 3x-4y=-63x−4y=−6 with y-axis.

To find : The coordinates of point of intersection ?

Solution :

Equation  3x-4y=-63x−4y=−6  ....(1)

y-axis means x=0.

To get the point of intersection substitute the value of y-axis in (1),

3(0)-4y=-63(0)−4y=−6

-4y=-6−4y=−6

y=\frac{6}{4}y=46

y=\frac{3}{2}y=23

The intersection point is (0,\frac{3}{2})(0,23) .

Therefore, the coordinates of points of intersection of graph of equation 3x-4y=-63x−4y=−6 with y-axis is (0,\frac{3}{2})(0,23) .

#Learn more

If y coordinate of a point is zero then where will this point lie in the coordinate plane