What are the dimensions of a,b,c,d in v= a+ bt+c÷d+t
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That's a pretty simple question.
The equation is v=a+bt+c/(d+t).
Clearly the dimension of lhs and rhs should match.
We know the dimensions of the lhs. They are Metre per second.
Now the constant d is added to t. For this it must have same dimensions. Thus dimension of d is second.
For the term c/(d+t) have the dimensions as Metre per second. C must have dimension as Metre.
And a must have Metre per second.
Using this we can easily find a/c.
Which comes out to be second inverse or hertz.
The equation is v=a+bt+c/(d+t).
Clearly the dimension of lhs and rhs should match.
We know the dimensions of the lhs. They are Metre per second.
Now the constant d is added to t. For this it must have same dimensions. Thus dimension of d is second.
For the term c/(d+t) have the dimensions as Metre per second. C must have dimension as Metre.
And a must have Metre per second.
Using this we can easily find a/c.
Which comes out to be second inverse or hertz.
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