find the probability of getting 53 sundays in a non leap year
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Answered by
699
We know that A non-leap year consists of 365 days.
In 365 days, Number of weeks = 52 and 1 day remaining.
For 52 weeks, There will be 52 Sundays.The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday.
Out of these 7 total outcomes, the favorable outcomes are 1.
Hence the probability of getting 53 Sundays = 1/7.
Hope this helps!
In 365 days, Number of weeks = 52 and 1 day remaining.
For 52 weeks, There will be 52 Sundays.The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday.
Out of these 7 total outcomes, the favorable outcomes are 1.
Hence the probability of getting 53 Sundays = 1/7.
Hope this helps!
Answered by
73
Answer:
We know that A non-leap year consists of 365 days.
In 365 days, Number of weeks = 52 and 1 day remaining.
For 52 weeks, There will be 52 Sundays.The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday.
Out of these 7 total outcomes, the favorable outcomes are 1.
Hence the probability of getting 53 Sundays = 1/7.
Hope this helps!
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