What are the divisibility rules for 4,6,7,9,11.
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4
THE NUMBER FORMED BY THE LAST 2 DIGITS SHOULD BE DIVISIBLE BY 4.
6
THE NUMBER SHOULD BE EVEN AND THE SUM OF THE DIGITS SHOULD BE DIVISIBLE BY 3.
7
MULTIPLY THE LAST DIGIT OF THE NUMBER BY 2 AND TEN SUBTRACT IT FROM THE NUMBER WITHOUT THE LAST DIGIT. IF THE ANSWER IS DIVISIBLE BY 7, THE NUMBER IS DIVISIBLE BY 7.
Ex: 651
LAST DIGIT*2 = 1*2 = 2
65-2 = 63, WHICH IS DIVISIBLE BY 7. SO, 651 IS DIVISIBLE BY 7.
9
THE SUM OF THE DIGITS OF THE NUMBER SHOULD BE DIVISIBLE BY 9.
11
THE DIFFERENCE BETWEEN THE SUM OF THE DIGITS ON THE ODD AND EVEN PLACES SHOULD BE 0 OR MULTIPLE OF 11
Ex: 1210
ODD PLACES SUM = 1 + 1 = 2
EVEN PLACES SUM = 2 + 0 = 2
DIFFERENCE = 2 - 2 = 0
SO, 1210 IS DIVISIBLE BY 11.
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