Question

what are the equations of logarithm

Answer 1

First, I'll expand the square on the right-hand side to be the explicit product of two logs:

log2(x2) = [log2(x)]2

log2(x2) = [log2(x)] [log2(x)]

Then I'll apply the log rule to move the "squared" from inside the log on the left-hand side of the equation, taking it out in front of that log as a multiplier:

2·log2(x) = [log2(x)] [log2(x)]

Then I'll move that term from the left-hand side of the equation to the right-hand side:

0 = [log2(x)] [log2(x)] – 2·log2(x)

This equation may look bad, but take a close look. It's nothing more than a factoring exercise at this point. So I'll factor, and then I'll solve the factors by using The Relationship:

0 = [log2(x)] [log2(x) – 2]

log2(x) = 0 or log2(x) – 2 = 0

20 = x or log2(x) = 2

1 = x or 22 = x

1 = x or 4 = x

Then my solution is:

x = 1, 4

Answer 2

here is your solution i have taken the solution from net because in didnt knew the answer i am in class 8 so sorry for this