Question

what are the factors of the following question.
a²+1÷a²+8(a+1÷a)+14​

Answer 1

Step-by-step explanation:

${a}^{2} + 1 \div {a}^{2} + 8(a + 1 \div a) + 14$

${a}^{2} + \frac{1}{ {a}^{2} } + 8(a + \frac{1}{a} ) + 14$

${a}^{2} + \frac{1}{ {a}^{2} } + 8 \times \frac{ {a}^{2} + 1 }{a} + 14$

${a}^{2} + \frac{1}{ {a}^{2} } + \frac{8( {a}^{2} + 1)}{a} + 14$

${a}^{2} + \frac{1}{ {a}^{2} } + \frac{8 {a}^{2} + 8}{a} + 14$

$\frac{ {a}^{4} + 1 + a \times (8 {a}^{2} + 8) + 14 {a}^{2} }{ {a}^{2} }$

$\frac{ {a}^{4} + 1 + 8 {a}^{3} + 8a + 14 {a}^{2} }{ {a}^{2} }$

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