Math, asked by Nagasudha2504, 8 months ago

What are the factors of the polynomial 9c3-1?

Answers

Answered by aryan90321

0

Answer:

84

Step-by-step explanation:

^ncr=n!/r!(n-r)!. ^9c3=9!/3!(9-3)!. = 9!/3!6! =9*8*7*6!/3!6! =9^3*8^4*7/3*2*1. =3*4* 7.

Answered by chandangowthami

0

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