What are the five important rules of Vedic maths with example
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TRICK NO:1 Multiplying numbers by 5
Therefore we get, 8640248 x 5 = 43201240
Therefore we get, 6386 x 5 = 31930
Simply, consider the given number to be ‘A’
Therefore, A X 5 = A X 10/2
which is again = A/2 X 10
TRICK NO:2 Multiplying any number by 11
For e.g.
Step I : Last digit remains same.
Step II : Add every digit starting from end to the previous one, move from right to left.
Step III : First digit remains same.
Therefore we get, 1353 x 11 = 14883
TRICK NO:3 [T20:20] * Applied when both the numbers are more than 10 and less than 20.
For e.g. 13 x 16
Step I : Sum of first number and last digit of second number or, last digit of first number and second number.
Step II : Answer of Step I x 10
Step III : Multiply last digit of both the numbers.
Step IV : Add the solutions of Step II and Step III.
Therefore we get, 13 x 16 = 208.
TRICK NO:4 [X + T10] * Applicable when sum of last digit of both the numbers gives 10, and first digit of both the numbers are same.
Step I: Multiply last digit of both the numbers.
Step II: Multiply the first digit of both the numbers with the digit that comes after that i.e., 7 comes after 6 so 6x7 in the above case.
Therefore we get, 63 x 67 = 4221.
TRICK NO:5 Multiplying numbers by 12.
Step I: Last digit will be double.
Step II: Multiply the previous digit with 2 and add it with the next digit. If there is any previous remainder add it with that.
Step III: First digit of the number is reused and kept same in the last step.
Therefore, we get, 1624 x 12 = 19488
Hope it helps you!!.
Therefore we get, 8640248 x 5 = 43201240
Therefore we get, 6386 x 5 = 31930
Simply, consider the given number to be ‘A’
Therefore, A X 5 = A X 10/2
which is again = A/2 X 10
TRICK NO:2 Multiplying any number by 11
For e.g.
Step I : Last digit remains same.
Step II : Add every digit starting from end to the previous one, move from right to left.
Step III : First digit remains same.
Therefore we get, 1353 x 11 = 14883
TRICK NO:3 [T20:20] * Applied when both the numbers are more than 10 and less than 20.
For e.g. 13 x 16
Step I : Sum of first number and last digit of second number or, last digit of first number and second number.
Step II : Answer of Step I x 10
Step III : Multiply last digit of both the numbers.
Step IV : Add the solutions of Step II and Step III.
Therefore we get, 13 x 16 = 208.
TRICK NO:4 [X + T10] * Applicable when sum of last digit of both the numbers gives 10, and first digit of both the numbers are same.
Step I: Multiply last digit of both the numbers.
Step II: Multiply the first digit of both the numbers with the digit that comes after that i.e., 7 comes after 6 so 6x7 in the above case.
Therefore we get, 63 x 67 = 4221.
TRICK NO:5 Multiplying numbers by 12.
Step I: Last digit will be double.
Step II: Multiply the previous digit with 2 and add it with the next digit. If there is any previous remainder add it with that.
Step III: First digit of the number is reused and kept same in the last step.
Therefore, we get, 1624 x 12 = 19488
Hope it helps you!!.
vishwas60:
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Answer:
The three rules of vedic maths with examples: 1. Navamguna Sutra : It is “the method of the Calculations” of the “Vedic Maths” which can “only applied” in the numbers that have 1 “multiplier” as “9”, “99”, or “999.
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