what are the foci of the ellipse 9x^2+16y^2=144
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9x 16y is equal to 12
thinker1:
the options are 1)7,02)0,73)0,root74)root7,0
did you find my message?
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9x^2 + 16Y^2 = 144
X^2/16 + Y^2/9 = 1
This is in the form of ellipse (x-h)^2/a^2 + (y-k)^2/b^2 = 1
Where a = 4,b=3, k=0, h=0.
The center of an ellipse(h,k) = (0,0).
The distance from the center to the ellipse = root (4)^2 - (3)^2
= root 16 - 9
= root 7.
The focus of an ellipse = (h+c,k)
= (0+root 7,0)
= root 7,0.
Hope this helps!
X^2/16 + Y^2/9 = 1
This is in the form of ellipse (x-h)^2/a^2 + (y-k)^2/b^2 = 1
Where a = 4,b=3, k=0, h=0.
The center of an ellipse(h,k) = (0,0).
The distance from the center to the ellipse = root (4)^2 - (3)^2
= root 16 - 9
= root 7.
The focus of an ellipse = (h+c,k)
= (0+root 7,0)
= root 7,0.
Hope this helps!
Thank You Thinker1 for the brainliest
that's ok.
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