Question

The difference between two numbers is 7. 6 times the smaller number added to the larger number is equal to 77. Find the numbers.

Answer 1

Heya....
Here is your answer ---

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Let the smaller number be x
Then, the larger number = x+7 (since the difference is 7)

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Now, ATQ :-
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=> 6x + x + 7 = 77

=> 7x + 7 = 77

=> 7x = 77 - 7

=> 7x = 70

=> x = 70/7

=> x = 10
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Smaller number = x = 10
Larger number = x + 7 = 10 + 7 = 17

HOPE IT HELPS....!!

Answer 2

hey@!
here's your answer!
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let the original smaller number be x .
and the larger number be y.

now,
According to the question,
y-x = 7 - no. (1)
and 6x + y = 77 - no.(2)

now solving both the simultaneous equations,
we'll get ...

( the equations have been solved in the attached picture) ( they have been solved on subtracting both the equations)

the value of the smaller no x will be = 10
now,
substituting the value of x in the first equation no.(1)

the value of y will be
y - x= 7
y-10 = 7
therefore,
y= 10+7
therefore,
y = 17


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Hope this helps you:)