Question

What are the intercepts of : 17y=−32x+12?

Answer 1

Solution:

Given 17y = -32x + 12

i) To find y -intercept , we must

take x = 0,

17y = (-32)×0 + 12

=> 17y = 12

=> y = 12/17

ii) To find x -intercept , we must

take y = 0,

17×0=(-32)x+12

=> 0 = -32x + 12

=> 32x = 12

=> x = 12/32

=> x = (4×3)/(4×8)

After cancellation,we get

=> x = 3/8

Therefore,

x-intercept (a) = 3/8

y-intercept (b) = 12/17

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