What are the last 5 digits of the sum 1+11+111+...+111...111 (111...111 has 2002 digits of 1)
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given that
l = 5
a = 1
d = 10
(l - a)/d
5 - 1/10
4/10
=1/2.5
l = 5
a = 1
d = 10
(l - a)/d
5 - 1/10
4/10
=1/2.5
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