Math, asked by kavithaamanapu12385, 9 months ago

What are the last two digits of  6 to the power of 2007 + 7 to the power of 2007​

Answers

Answered by rikita004
10

6 to the power of 2007 = 6.53558150E+19

7 to the power of 2007=

1.31169121E+23

mark me as the brainliest if it helps

Answered by ishaaryan2003
1

Answer:

6 TO THE POWER OF 2007=6.53558150E+19

7 TO THE POWER OF 2007=1.31169121E+23

Step-by-step explanation:

Similar questions