Math, asked by sundararajanchitra66, 8 months ago

what are the operations are satisfied under closure property in a set of integers ?

Answers

Answered by BrainlyShivansh
1

Answer:

subtraction, addition and multiplication

Answered by subechhadatta
0

Answer:

Closure property says that if for any two integers a and b, a∗b is also an integer then the set of integers is closed under ∗

where ∗ represents +,−,× or ÷

For example:- Take 4 and 8

Now, 4+8=12 is an integer

4×8=32 is an integer

4−8=−4 is an integer

But 4÷8=

8

4

=

2

1

is not an integer

Hence, set of integer is closed under +,−× but not closed under ÷.

COMMUTATIVE PROPERTY OF INTEGERS - DEFINITION

Take any two numbers a and b in your mind. Now add a and b, which comes as a+b.

Add b and a, which comes to be b+a.

Aren't they same ?

Yes, they are equal.

This is because of commutative property.

So, let's have a look at commutative property of numbers which says that we can swap the numbers and still we get the same answer.

It is a property that associates with binary operations or functions like addition, multiplication.

COMMUTATIVE PROPERTY OF INTEGERS - DEFINITION

What about subtraction of numbers ?

Take a and b as two integers and subtract them i.e. a−b.

Now, subtract a from b i.e. b−a.

Are they same ?

No, they are not equal.

So, commutative property does not hold for subtraction.

Similarly, it does not hold for division.

ASSOCIATIVE PROPERTY OF INTEGERS - DEFINITION

Associative property states that, for any three elements(numbers) a,b and c we have

a∗(b∗c)=(a∗b)∗c, where ∗ represents a binary operation.

Let's take ∗ as addition(+)

Then, we have a+(b+c)=(a+b)+c

For eg:- For 2,5 and 11

2+(5+11)=2+16=18 and (2+5)+11=7+11=18

For multiplication

2×(5×11)=2×55=110 and (2×5)×11=10×11=110

Hence, a∗(b∗c)=(a∗b)∗c is true for addition and multiplication.

ASSOCIATIVE PROPERTY OF INTEGERS - EXAMPLE

What about subtraction and division ?

Associative property does not hold for subtraction and division

Let's take an example :

For 4,6 and 12

4÷(6÷12)=4÷

12

6

=4÷

2

1

=

2

1

4

=4×2=8 and

(4÷6)÷12=

6

4

÷12=

3

2

÷12=

12

3

2

=

3×12

2

=

3×6

1

=

18

1

=8

Therefore, a∗(b∗c)=(a∗b)∗c is not true for division.

Also, 4−(6−12)=4−(−6)=4+6=10 and (4−6)−12=−2−12=−14

=10

Hence, a∗(b∗c)=(a∗b)∗c is not true for subtraction as we

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