Question

What are the other factors of p(x) 3x^4 + 4x^3 + 4x^2 – 8x – 3 if one factor is (3x + 1)​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$x {}^{3} + x {}^{2} + x - 3 \: \: is \: \: other \: \: factor$

Other factor = (x^3 + x^2 + x – 3)

x^3 + x^2 + x – 3

Factors of 3 = ± 1, ± 3

p(–1) = (–1)^3 + (–1)^2 + (–1) – 3

= –1 + 1 –1 –3

= 0

p(–1) = 1^3 + 1^2 + 1 – 3

= 3 – 3 = 0

For second attachment

Other factors = (x – 1) and (x^2 + 2x + 3)