Question

What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results?
a. H₂S₄O₆
b. Fe₃O₄
c. CH₃CH₂OH
d. CH₃COOH

Answer 1

where is the under line mate

Answer 2

Dear Student,

● Answers with Explaination -

Aa we know, oxidation number of oxygen is -2 and that of hydrogen is +1.

(a) H₂S₄O₆

Sum of oxidation states of all entities is equal to charge on the compound.

2×H + 4×S + 6×O = 0

2×(+1) + 4×S + 6×(-2) = 0

2 + 4S - 12 = 0

4S = 10

S = +2.5

(b) Fe₃O₄

Sum of oxidation states of all entities is equal to charge on the compound.

3×Fe + 4×O = 0

3Fe + 4×(-2) = 0

3Fe = 8

Fe = +8/3

(c) CH₃CH₂OH

2×C + 6×H + 1×O = 0

2C + 6×(+1) + 1×(-2) = 0

2C + 6 - 2 = 0

2C = -4

C = -2

(d) CH₃COOH

2×C + 4×H + 2×O = 0

2C + 4×(+1) + 2×(-2) = 0

2C + 4 - 4 = 0

C = 0

Hope this helps you...