What are the points where the graph of P(x)=x^2+x-12
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Answered by
7
x^2+x-12
x^2+4x-3x-12
x(x+4)-3 (x+4)
x=3,-4
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x^2+4x-3x-12
x(x+4)-3 (x+4)
x=3,-4
mark it brainlist
Answered by
4
Answer:
Refer the attached figure.
Step-by-step explanation:
Given : Polynomial p(x)=x^2-x-12p(x)=x
2
−x−12 .
To find : The graph of the polynomial ?
Solution :
We plot the graph of polynomial on different value of x and y,
Since it is quadratic function it form a parabola.
The number of zeros are 2 and the zeros are the points where the graph of the polynomial intersects the x-axis.
Zeros are : (-3,0) and (4,0)
On y-axis the point is (0,-12).
The vertices of the parabola is (0.5,-12.25).
Refer the attached figure below.
#Learn more
Draw the graph of the polynomial and find the zeros.justify the answer.p(x)= x²-1
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