Question

What are the possible expressions for the dimensions of a cuboid, whose volume=36kx^2y-21kxy^2+3ky^3?

Answer 1

let tne dimensions of a cuboid are

length =l, breadth = b, height=h

volume = 36kx^2y-21kxy^2+3ky^3

lbh= 3ky[12x^2-7xy^2+y2]

= 3ky[12x^2-4xy-3xy+y^2]

=3ky[4x(3x-y)-y(3x-y)]

=3ky(3x-y)(4x-y)

therefore

l=3ky, b=(3x-y), h=(4x-y)

you can take any of three factors as l or b or h

Answer 2

Answer:

hope above answer is helpful