Question

What are the possible polynomial expressions for the dimensions of the cuboids whose
volumes are given below.. a)12y2 + 8y - 20.​

Answer 1

Answer:

Step-by-step explanation:

12y2 +8y-20.

Take 4 common

4(3y2 +2y - 5)=0

3y2 +2y -5=0

3y2 -3y+5y -5=0

3y(y-1)+5(y-1)=0

(3y-1) (y-1)

Therefore. Y-1=0

y=1

Answer 2

Answer:

Please Mark me as BRAINLIST

Step-by-step explanation:

Given volume of cuboid = 12y

2

+8y−20

=4(3y

2

+2y−5)

=4(3y

2

+5y−3y−5)

=4[y(3y+5)−1(3y+5)]

=4(3y+5)(y−1)

Then dimensions of cuboid are 4,(3y+5), and (y−1).