Question

What are the products at cathode and anode if we carry out the electrolysis of NaCl(aq)diluted and NaCl(aq) concentrated using platinum electrode ​

Answer 1

HEY MATE !!!

During the electrolysis of dilute NaCl solution, Na+, Cl- and water are present.  

Catode: 2H2O + 2e^(-) --> H2 + 2OH^(-)  

Anode: 2H2O --> O2 + 4H^(+) + 4e^(-)  

(or) 2Cl^(-)(aq) --> Cl2(g) + 2e^(-)  

 

When concentrated NaCl solution undergoes electrolysis, sodium hydroxide and hydrogen are produced at the cathode while chlorine is produced at the anode.  

Cathode: 2H2O + 2e^(-) --> H2 + 2OH^(-)  

Anode: 2Cl^(-) --> Cl2 + 2e^(-)

Cheers !!!

Answer 2

$\huge {\boxed {\texttt \color{red}{ELLO!! }}}$

$\underline {\boxed {\texttt \color{red}{ANSWER}}}$

$\underline { \mathfrak \color{green}{AT \: CATHODE }}$

Na^+1 + 1e--->Na.

$\underline { \mathfrak \color{green}{AT \: ANODE}}$

Ions discharged =OH^-1,Cl^-1.

Since,

Cl^-1 lies below OH^-1 it will be discharged.

Cl^-1 - 1e ---> Cl ×2

Cl +Cl ---> Cl2.

$\underline {\huge { \mathfrak \color{green}{HOPE IT HELPS }}}$