Math, asked by thyag, 1 year ago

What are the real roots of 2x^2-6x+3=0

Answers

Answered by Panzer786
0
Heya !!!




P(X) = 2X² - 6X + 3 = 0





Here,



A = 2 , B = -6 and C = 3





Given that,


Roots of the given equation is real and equal





Each roots = -B/2A





=> -(-6)/ 2 × 2





=> 6/4





=> 3/2



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thyag: Can u pls solve it with quadratic formula
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