Question

What are the roots of the quadradic equation 2 x2 + 6 = -7 x​

Answer 1

Answer:

2x^2+7x+6=0

2x^2+4x+3x+6=0

2x(x+2)+3(x+2)=0

(2x+3)(x+2)=0

either 2x+3=0

x=-3/2

or x+2=0

x=-2

Answer 2

Step-by-step explanation:

$2 \times 2 + 6 = - 7x \\ 4 + 6 = - 7x \\ 10 = - 7x \\ - 7x = 10 \\ x = - \frac{10}{7} \\ = 1 \frac{3}{7}$

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