Question

What are the roots of the quadratic equation 2x²-7x+6=0 ?​

Answer 1

Answer:

2x^2 -4x-3x+6

2x(x-2)-3(x-2)

so

(2x-3) (x-2)

x=3/2 or2

Answer 2

Answer:

$2 {x}^{2} - 7x + 6 = 0 \\ \implies \: 2 {x}^{2} - 4x - 3x + 6 = 0 \\ \implies \: 2x(x - 2) - 3(x - 2) = 0 \\ \implies \: (x - 2)(3x - 2) = 0 \\ \\ \\ \therefore \: x - 2 = 0 \: \: or \: 3x - 2 = 0 \\ \implies \: x = 2 \: \: or \: \: x = \frac{2}{3}$