Question

What are the solution(s) of the system of equations 2x+y=1, x-y=3?

Answer 1

$2x + y = 1---(i)\\\\x - y = 3---(ii)\\\\we\:get\:to\:know\:that,\\\frac{2}{1}\neq \frac{1}{-1}\\a_{1} = 2\:and\:a_{2}=1\\b_{1} = 1\:and\:b_{2} = -1\\\\By\:adding\:(i)\:and\:(ii)\\\\(2x + y) + (x - y) = 1 + 3\\\\2x + y + x - y = 4\\\\3x = 4\\\\x = \frac{4}{3} \\\\Now, Substitute\:the\:value\:of\:'x'\:in\:equation\:(i)\\\\We\:get,\\\\2(\frac{4}{3} ) + y = 1\\\\\frac{8}{3} + y = 1\\\\y = 1 - \frac{8}{3} \\\\y = \frac{-5}{3}$