What is the distance between the origin and the midpoint of (1,2) and (−3,6)?
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Answer:
2.82 unit
Step-by-step explanation:
let (1,2) = x
(-3,6)=y
distance b/w x and y
= square root of [(-3-1)^2 +(6-2)^2]
= square root of [(-4)^2 + (4)^2]
= square root of [16+16]
= 4 root 2
distance between the origin and the midpoint
=4 root 2 / 2
=2 root 2
= 2*1.41
= 2.82 unit
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