What are the three consecutive numbers such that the sum of the second number and the third number exeeds the first by 14
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Let the three consecutive numbers be n , n+1 , n+2.
ATQ,
n+ 1+ n+2=n +14
2n+3= n + 14.
2n - n = 14 -3
n = 11.
n + 1 = 11+1 = 12
n+2 = 11+2 =13.
The three consecutive numbers are 11, 12, 13.
ATQ,
n+ 1+ n+2=n +14
2n+3= n + 14.
2n - n = 14 -3
n = 11.
n + 1 = 11+1 = 12
n+2 = 11+2 =13.
The three consecutive numbers are 11, 12, 13.
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