Question

What are the values for x & y in 72x23y for it to be perfectly divisible by 88?

Answer 1

we have to find the values of x and y for which 72x23y is perfectly divisible by 88.

Solution : 72x23y is perfectly divisible by 88.

it means, 72x23y is also divisible by 11 and 8.

divisibility of 11 : sum of digits of odd position - sum of digits of even position = multiple of 11

here 7 + x + 3 - (2 + 2 + y) = 10 + x - 4 - y

= 6 + x - y = 0 or 11 .... (1)

divisiblity of 8 : last three term must be divisible by 8.

so, 23y must be divisible by 8, it is divisible only when y = 2

from equations (1),

6 + x - y = 0 or 11

⇒6 + x - 2 = 0 ⇒x = -4 (not possible)

6 + x - 2 = 11 ⇒x = 7

Therefore x = 7 and y = 2

Answer 2

Answer:

7 and y = 2

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