Question

what are the values of all six ratios in trigonometry

Answer 1

Hey there!

TRIGONOMETRIC RATIOS:
Considering angle α

sine α = Perpendicular/Hypotenuse = AC/BC

cosine α = Base/Hypotenuse = AB/BC

tangent α = Perpendicular/Base = AC/AB

cotangent α = Base/Perpendicular = AB/AC

secant α = Hypotenuse/Base = BC/AB

cosecant α = Hypotenuse/Perpendicular = BC/AC

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Answer 2

Sin0°=0

Sin 30°=1/2

Sin45°=
$1 \div \sqrt{2}$

Sin60°=
$\sqrt{3 } \div 2$
Sin90°=1

Cos0°=1

Cos30°=
$\sqrt{3} \div 2$
Cos45°=
$1 \div \sqrt{2}$
Cos60°=1/2

Cos90°=0

Tan0°=0

Tan30°=
$1 \div \sqrt{3}$
Tan45°=1

Tan60°=
$\sqrt{3}$
Tan90°=
$\infty$

Cosec0°=
$\infty$
Cosec30°=2

Cosec45°=
$\sqrt{2}$
Cosec60°=
$2 \div \sqrt{3}$
Cosec90°=1


Sec0°=1

Sec30°=
$2 \div \sqrt{3}$
Sec45°=
$\sqrt{2}$

Sec60°=2

Sec90°=
$\infty$
Cot0°=
$\infty$
Cot30°=
$\sqrt{3}$
Cot45°=1

Cot60°=
$1 \div \sqrt{3}$
Cot90°=1