Math, asked by rashedraj94, 11 months ago

what are the values of M and N respectively if M39048458N is divisible by both 8 and 11, where M and N are single-digit intergers?

Answers

Answered by Shivam96419
2


Well M39048458N is divisible by 8 and 11. For the number to be divisible 8, the last four digits should be divisible by 8. So N should be 4 for4584 is divisible by 8.

So we have M390484584. Next the sum of the even digits must be the same as the sum of odd digits, or the difference should be 11, in order to be divisible by 11. The sum of the numbers in the even position is = 3+0+8+5+4 = 20.

The sum of the numbers in the odd position is = M+9+4+4+8 = M+25. So M should be 6.

So the number ought to be 6390484584.

Check: 6390484584/8 = 798810573

6390484584/11 = 580953144

So the number is 6390484584

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Answered by ashishshanavas
0

Answer:

Step-by-step explanation:

Well M39048458N is divisible by 8 and 11. For the number to be divisible 8, the last three digits should be divisible by 8. So N should be 4 for4584 is divisible by 8.

So we have M390484584. Next the sum of the even digits must be the same as the sum of odd digits, or the difference should be 11, in order to be divisible by 11. The sum of the numbers in the even position is = 3+0+8+5+4 = 20.

The sum of the numbers in the odd position is = M+9+4+4+8 = M+25. So M should be 6.

So the number ought to be 6390484584.

Check: 6390484584/8 = 798810573

6390484584/11 = 580953144

So the number is 6390484584

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