What are the x-intercepts of the function f(x) = –2x^2 – 3x + 20?
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Answer:
Step-by-step explanation:
put f(x) = 0
-2x² - 3x + 20 =0
2x² + 3x - 20 = 0
2x² + 8x - 5x - 20 = 0
2x(x + 4) - 5(x + 4) = 0
(2x - 5)(x + 4) = 0
x = 5/2 , -4 are the x intercepts
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