What are the zeroes of p(x) = x2+ 7x + 12 :?
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2x+7x+12=0
2x+7x=-12
X+7x=-12/6
X+7x=-3
X+X=-3/7
2x=-3/7
X=-3/7/2
X=-6/7
2x+7x=-12
X+7x=-12/6
X+7x=-3
X+X=-3/7
2x=-3/7
X=-3/7/2
X=-6/7
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