What are the zeroes of polynomial mx 2 +(m+n) x+n
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mx² +(m+n)x +n =0
⇒mx² +mx +nx +n=0
⇒mx(x+1) +n(x+1) =0
⇒(x+1)(mx+n)=0
⇒(x+1) =0 or (mx+n) =0
⇒x = -1 or -n/m
⇒mx² +mx +nx +n=0
⇒mx(x+1) +n(x+1) =0
⇒(x+1)(mx+n)=0
⇒(x+1) =0 or (mx+n) =0
⇒x = -1 or -n/m
Answered by
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Answer:
Step-by-step explanation:mx² +(m+n)x +n =0
⇒mx² +mx +nx +n=0
⇒mx(x+1) +n(x+1) =0
⇒(x+1)(mx+n)=0
⇒(x+1) =0 or (mx+n) =0
⇒x = -1 or -n/m
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