Question

What are
the zeroes of quadratic polynemial
y^2-3y+2
​

Answer 1

sorry i dont this answer

Answer 2

Step-by-step explanation:

y^2-3y+2=0

y^2-y-2y+2=0

y(y-1)-2(y-1)=0

(y-2)(y-1)=0

y=2,1

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