Question

What are the zeroes of the polynomial p (x)=3-x^2.

Answer 1

f(x)=3-x^2
3-x^2=0
3=x^2
x=√3

Answer 2

HERE IS YOUR ANSWER...⤵⤵

$\underline{SOLUTION}$ ➡

$Given ,\\ \\ p(x) = 3 - x {}^{2} \\ \\ \\ To \: \: find : Zeros \: of \: p(x) \\ \\ Now, \\ \\ p(x) = 0 \\ \\ = > 3 - x {}^{2} = 0 \\ \\ = > - x {}^{2} = - 3 \\ \\ = > x{}^{2} = 3 \\ \\ = > x = ± \sqrt{3} \\ \\So , \\ \\The \: zeros \: of \: p(x) = 3 - x {}^{2} \: \: are \: \: : \\ \sqrt{3} \: ,\: \: - \sqrt{3}$

$\underline{ANSWER}$ ➡

$\sqrt{3} \: ,\: \: - \sqrt{3}$

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