Question

What are the zeros of the polynomials
p(x)=x²-9x+14
​

Answer 1

Answer:

zeroes of given polynomial are

2 or 7

Step-by-step explanation:

x²-9x+14=0

x²-2x-7x+14=0

x(x-2)-7(x-2)=0

(x-2)(x-7)=0

x-2=0. or. x-7=0

x=2. or. x=7

Answer 2

Answer:

$\huge{ \bold{ \mathfrak{ \red{ answer}}}}$

FACTORISE THE GIVEN EQUATION--

p(x) = x²-9x+14

p(x) = 0

x²-9x+14 = 0

x²-7x-2x+14 = 0

x(x-7) -2(x-7) =0

(x-2) (x-7)

FOR ZEROES-

x - 2 = 0 AND x - 7 = 0

x = 2... x = 7.....

$<marquee >$

hope this helps you✌✌