Question

What are the zeros of the quadratic function f(x) = 8x2 – 16x – 15?

Answer 1

Hello user your answer...


f(x)=8×^2-16x-15,using the quadractic formula.it will result to . .

x=1sqrt(23/8),x=1+sqrt(23/8)..


or the answer

X=16+√736/16or
X=4+√46/4...


Thanks!!

Answer 2

Answer:

x = 2.696, x = -0.696

Step-by-step explanation:

We are given the following function of x and we are to find the zeros for the given quadratic function:

$f(x)= 8x^2-16x-15$

To find its zeros, we will use the quadratic formula:

$x=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

Substituting the values in the formula where $a=8$, $b=-16$ and $c=-15$.

$x=\frac{-(-16)+-\sqrt{(-16)^2-4(8)(-15)} }{2(8)}$

$x=\frac{16+-\sqrt{736} }{16}$

$x=\frac{16+27.13}{16}$ , $x=\frac{16-27.13}{16}$

$x = 2.696$ , $x=-0.696$

Therefore, the solutions are 2.696 and -0.696.