Question

What are the zeros of the quadratic function f(x) = 8x2 – 16x – 15?

Answer 1

Hello user your answer...

f(x)=8x^2-16x-15,using the quadratic formula it will result to....
X=1-sqrt(23/8),x=1+sqrt(23/8)...

Or the answer...

x=16+√736/16 or
x=4+√46/4...

Thanks!!

Thanks!!

Answer 2

Answer:

The zeros of the equations  are $1 + \frac{\sqrt{46} }{4}$    and $1 - \frac{ \sqrt{46} }{4}$  

Step-by-step explanation:

Given equation  $8x^{2} - 16x -15$

compare the given equation with $ax^{2} + bx +c =0$  

⇒ a = 8,    b = -16   and c = -15  

⇒ b² - 4ac  = (-16)² - 4 (8)(-15)  = 256 + 480 = 736

⇒ find the solution of the equation  x = (-b ± $\sqrt{b^{2} -4ac}$) / 2a

⇒ x = [- (-16) ± $\sqrt{736}$ ] / 2(8)

      =  (16 ± $\sqrt{16(46)}$)/ 16

      =  (16 ± 4√46) / 16  

 x = (16 + 4√46) / 16             and             x = (16 - 4√46) / 16

    = 1 + (√46)/ 4                                          =  1 - (√46)/4      

the zeros of the equations  are $1 + \frac{\sqrt{46} }{4}$    and $1 - \frac{ \sqrt{46} }{4}$