What are those two numbers whose sum is 58 and difference is 28 ?
Answers
Answered by
55
Let that numbers be X and Y
then by given conditions
x+y=58
×-y=28
let us cross multiply it
28×(x+y)=58×(x-y)
28x+28y=58x- 58y
now let us transform it
28x-58x=-58y- 28y
-30x=-86y
30x=86y
x/y=86/30
x/y=43/15
so two numbers are 43 and 15......:)
hope it helps!!!!
*Vinay*;)
then by given conditions
x+y=58
×-y=28
let us cross multiply it
28×(x+y)=58×(x-y)
28x+28y=58x- 58y
now let us transform it
28x-58x=-58y- 28y
-30x=-86y
30x=86y
x/y=86/30
x/y=43/15
so two numbers are 43 and 15......:)
hope it helps!!!!
*Vinay*;)
gigamind:
finally you got the answer fine. but we should use only one variable not X and Y. is it possible to solve by using one variable
pls mark as brainlist if possible
ya I try to do it in one variable
just i search in brain list but your name wasn't appear...i will try when i free
ok
Answered by
1
Answer:
first number is 48 and
second number is 15
Step-by-step explanation:
Let that numbers be X and Y
then by given conditions
x+y=58
×-y=28
let us cross multiply it
28×(x+y)=58×(x-y)
28x+28y=58x- 58y
now let us transform it
28x-58x=-58y- 28y
-30x=-86y
30x=86y
x/y=86/30
x/y=48/15
so two numbers are 48 and 15
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