Question

What are thr possible polynomial expressions for the dimensions of the cuboid whose volume is 14x*2+21x-35

Answer 1

The possible polynomial expressions for the dimensions of the cuboid whose volume is $14x^2+21x-35$ is $\boxed{1, (x-1), (14x+35)}$

Step-by-step explanation:

The given volume of the cuboid is

$14x^2+21x-35$

$=14x^2-14x+35x-35$

$=14x(x-1)+35(x-1)$

$=(x-1)(14x+35)$

$=1.(x-1).(14x+35)$

Therefore, possible dimensions of the cuboid could be

$1, (x-1), (14x+35)$

Hope this helps.

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Answer 2

The dimensions of cuboid are 7, (x-1), and (2x+5).

Step-by-step explanation:

Since we have given that

Volume is given by

$14x^2+21x-35$

We need to find the dimensions of cuboid.

First we common 7 from the expression:

$7(2x^2+3x-5)$

Now, we will split the middle term of quadratic equation.

$2x^2+3x-5\\\\=2x^2+5x-2x-5\\\\=x(2x+5)-1(2x+5)\\\\=(x-1)(2x+5)$

Hence, the dimensions of cuboid are 7, (x-1), and (2x+5).

#learn more:

https://brainly.in/question/13501175 Answered by Sonuvuce

Topic: Quadratic equation