Question

what are three consecutive integer whose sum is 63.​

Answer 1

Here we will use algebra to find three consecutive integers whose sum is 63. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 63. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 63


To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 63
3X + 3 = 63

3X + 3 - 3 = 63 - 3
3X = 60

3X/3 = 60/3
X = 20

Which means that the first number is 20, the second number is 20 + 1 and the third number is 20 + 2. Therefore, three consecutive integers that add up to 63 are 20, 21, and 22.

20 + 21 + 22 = 63

We know our answer is correct because 20 + 21 + 22 equals 63 as displayed above.

Hope it works for you ✌✌✌

Answer 2

Answer:

The three consecutive integers whose sum is $63$ is $20,21,22$

Step-by-step explanation:

Given:

To find the three consecutive integers whose sum is $63$.​

Let the three consecutive integers be $x,x+1,x+2$

Then applying the given condition we get

$x+x+1+x+2=63\\\\3x+3=63\\\\3x=60\\\\x=20$

So terms will be

$x=20\\\\x+1=21\\\\x+2=22$