What are two numbers that add up to 32 but have a difference of 8
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2
Answer:
the required answer is 20&12
Answered by
0
Answer:
Step-by-step explanation:
Let bigger number be x and smaller be y
by condition x+y=32(1) and x-y=8(2)
By elimination
2x=40
x=40/2
x=20
putting the value of x in (1) we get,
20+y=32
y=32-20
y=12
Therefore the numbers are 20 and 12
Thanks
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