what are two numbers that have a product of 437 and a difference of four?
Answers
Answered by
3
23,19
Step-by-step explanation:
let the numbers be a,b
axb=437
a-b=4
use : (a+b)^2 =(a-b)^2 + 4ab
(a+b)^2 =4^2 +4(437)
=16 + 1748
=1764
(a+b) = 42
now,
a+b=42
a-b=4
so,
a =23 , b=19
Similar questions