Question

What are x and y if 4x−4y=−16 and x−2y=−12?

Answer 1

Solution:

Given system of equations:

4x-4y=-16

Divided each term by 4 , we get

x-y= -16 ---(1)

and

x - 2y = -12 ----(2)

Subtract (2) from(1),we get

y = -4

Now , put y = -4 in equation (1),

we get

x - (-4) = -16

=> x + 4 = -16

=> x = -16 - 4

=> x = -20

Therefore,

x = -20, y = -4

••••

Answer 2

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ANSWER :

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GIVEN :

4x - 4y = -16 ____(1)

x - 2y = -12 ____(2)

TO FIND :

The value of x and y .

SOLUTION:

Divide the equation (1) by 4,,,

(1) ÷4 => x - y = - 4 ____(3)

Subtract (2) and (3) ,,,,

(2) => x - 2y = -12

(3) => x - y = -4

(-) (+) (+)

________________

-y = -8

y = 8

Substitute the value of y = 8 in (3),,,

(3) => x - 8 = -4

x = 8 - 4

x = 4

The value of x and y is 4 and 8.

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