Question

What can be the minimum number of days in any seven consecutive year?
X 1. 2558
X2 2556
X 3. 2557
✓4 2555​

Answer 1

the chances are

if year 1 is a leap year number of days in 7 years=2557

year 1 leap

year 2

year 3

year 4

year 5 leap

year 6

year 7

if year 2 is leap year, number of days in 7 years=2557

year 1

year 2 leap

year 3

year 4

year 5

year 6 leap

year 7

if year 3 is leap year,number of days in 7 years=2557

year 1

year 2

year 3 leap

year 4

year 5

year 6

year 7 leap

if year 4 is leap,number of days in 7 years=2556

year 1

year 2

year 3

year 4 leap

year 5

year 6

year 7

so minimum number of days is 2556

Answer 2

Given: Seven consecutive years are randomly chosen

To find: Minimum number of days that is possible in these seven years

Explanation: A leap year is a year that has 366 days because of 1 extra day that occurs in the month of February. It occurs every 4 years. Thus we need to make sure that while selecting these 7 years, minimum number of leap years have to be selected. In 7 years, the minimum number of leap years can be 1.

For example: Take 2013,2014,2015,2016,2017,2018,2019. Here, only one year that is 2016 is a leap year and remaining 6 are normal years.

Now, days in a normal year= 365

Days in 6 such normal years= 365*6= 2190

Days in one leap year= 1*366 = 366

Total days= 2190+366= 2556

Therefore, the minimum number of days in seven consecutive years is 2556.