Math, asked by varshneysamyakoxg8tj, 1 year ago

What can be the solution of question-19

Attachments:

vol: (x-1)

Answers

Answered by S1dSweety

Step  1  :

Equation at the end of step  1  :

(((2 • (x3)) + 5x2) - 5x) - 2

Step 2 :

Equation at the end of step  2  :

((2x3 + 5x2) - 5x) - 2

Step  3  :

Checking for a perfect cube :

3.1    2x3+5x2-5x-2 is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  2x3+5x2-5x-2

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -5x-2
Group 2:  5x2+2x3

Pull out from each group separately :

Group 1:   (5x+2) • (-1)
Group 2:   (2x+5) • (x2)

Attachments:

varshneysamyakoxg8tj: but what is the integral zero

S1dSweety: if an integer a is a zero of a polynomial function withintegral. coefficients and a leading coefficient of 1, then a is a factor of the constant term of the. polynomial.Integral Zeros

varshneysamyakoxg8tj: okkkkk

S1dSweety: Mark my answer as brainliest ones If it helps you

varshneysamyakoxg8tj: I can't mark u as a brainliest till some other person answer this question

varshneysamyakoxg8tj: the brainliest button is disabled at the moment

S1dSweety: ohh okay

Previous Question

Next Question